-(z+6)+(3z+1)=4(z+1)

Solution for -(z+6)+(3z+1)=4(z+1) equation:

Simplifying
-1(z + 6) + (3z + 1) = 4(z + 1)

Reorder the terms:
-1(6 + z) + (3z + 1) = 4(z + 1)
(6 * -1 + z * -1) + (3z + 1) = 4(z + 1)
(-6 + -1z) + (3z + 1) = 4(z + 1)

Reorder the terms:
-6 + -1z + (1 + 3z) = 4(z + 1)

Remove parenthesis around (1 + 3z)
-6 + -1z + 1 + 3z = 4(z + 1)

Reorder the terms:
-6 + 1 + -1z + 3z = 4(z + 1)

Combine like terms: -6 + 1 = -5
-5 + -1z + 3z = 4(z + 1)

Combine like terms: -1z + 3z = 2z
-5 + 2z = 4(z + 1)

Reorder the terms:
-5 + 2z = 4(1 + z)
-5 + 2z = (1 * 4 + z * 4)
-5 + 2z = (4 + 4z)

Solving
-5 + 2z = 4 + 4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-4z' to each side of the equation.
-5 + 2z + -4z = 4 + 4z + -4z

Combine like terms: 2z + -4z = -2z
-5 + -2z = 4 + 4z + -4z

Combine like terms: 4z + -4z = 0
-5 + -2z = 4 + 0
-5 + -2z = 4

Add '5' to each side of the equation.
-5 + 5 + -2z = 4 + 5

Combine like terms: -5 + 5 = 0
0 + -2z = 4 + 5
-2z = 4 + 5

Combine like terms: 4 + 5 = 9
-2z = 9

Divide each side by '-2'.
z = -4.5

Simplifying
z = -4.5