-(z+5)+(4z+1)=2(z+1)

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Solution for -(z+5)+(4z+1)=2(z+1) equation:


Simplifying
-1(z + 5) + (4z + 1) = 2(z + 1)

Reorder the terms:
-1(5 + z) + (4z + 1) = 2(z + 1)
(5 * -1 + z * -1) + (4z + 1) = 2(z + 1)
(-5 + -1z) + (4z + 1) = 2(z + 1)

Reorder the terms:
-5 + -1z + (1 + 4z) = 2(z + 1)

Remove parenthesis around (1 + 4z)
-5 + -1z + 1 + 4z = 2(z + 1)

Reorder the terms:
-5 + 1 + -1z + 4z = 2(z + 1)

Combine like terms: -5 + 1 = -4
-4 + -1z + 4z = 2(z + 1)

Combine like terms: -1z + 4z = 3z
-4 + 3z = 2(z + 1)

Reorder the terms:
-4 + 3z = 2(1 + z)
-4 + 3z = (1 * 2 + z * 2)
-4 + 3z = (2 + 2z)

Solving
-4 + 3z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-4 + 3z + -2z = 2 + 2z + -2z

Combine like terms: 3z + -2z = 1z
-4 + 1z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-4 + 1z = 2 + 0
-4 + 1z = 2

Add '4' to each side of the equation.
-4 + 4 + 1z = 2 + 4

Combine like terms: -4 + 4 = 0
0 + 1z = 2 + 4
1z = 2 + 4

Combine like terms: 2 + 4 = 6
1z = 6

Divide each side by '1'.
z = 6

Simplifying
z = 6

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