-(z+1)+2(z-2)=0

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Solution for -(z+1)+2(z-2)=0 equation:


Simplifying
-1(z + 1) + 2(z + -2) = 0

Reorder the terms:
-1(1 + z) + 2(z + -2) = 0
(1 * -1 + z * -1) + 2(z + -2) = 0
(-1 + -1z) + 2(z + -2) = 0

Reorder the terms:
-1 + -1z + 2(-2 + z) = 0
-1 + -1z + (-2 * 2 + z * 2) = 0
-1 + -1z + (-4 + 2z) = 0

Reorder the terms:
-1 + -4 + -1z + 2z = 0

Combine like terms: -1 + -4 = -5
-5 + -1z + 2z = 0

Combine like terms: -1z + 2z = 1z
-5 + 1z = 0

Solving
-5 + 1z = 0

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 1z = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 1z = 0 + 5
1z = 0 + 5

Combine like terms: 0 + 5 = 5
1z = 5

Divide each side by '1'.
z = 5

Simplifying
z = 5

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