-(y-4)+3y=(y+1)

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Solution for -(y-4)+3y=(y+1) equation: 



-(y-4)+3y=(y+1)

We move all terms to the left:

-(y-4)+3y-((y+1))=0

We add all the numbers together, and all the variables

3y-(y-4)-((y+1))=0

We get rid of parentheses

3y-y-((y+1))+4=0



We calculate terms in parentheses: -((y+1)), so:

(y+1)

We get rid of parentheses

y+1

Back to the equation:

-(y+1)



We add all the numbers together, and all the variables

2y-(y+1)+4=0

We get rid of parentheses

2y-y-1+4=0

We add all the numbers together, and all the variables

y+3=0

We move all terms containing y to the left, all other terms to the right

y=-3

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