-(x-8)+4x=2(-x+8+4x)+x

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Solution for -(x-8)+4x=2(-x+8+4x)+x equation: 



-(x-8)+4x=2(-x+8+4x)+x

We move all terms to the left:

-(x-8)+4x-(2(-x+8+4x)+x)=0

We add all the numbers together, and all the variables

-(x-8)+4x-(2(3x+8)+x)=0

We add all the numbers together, and all the variables

4x-(x-8)-(2(3x+8)+x)=0

We get rid of parentheses

4x-x-(2(3x+8)+x)+8=0



We calculate terms in parentheses: -(2(3x+8)+x), so:

2(3x+8)+x

We add all the numbers together, and all the variables

x+2(3x+8)

We multiply parentheses

x+6x+16

We add all the numbers together, and all the variables

7x+16

Back to the equation:

-(7x+16)



We add all the numbers together, and all the variables

3x-(7x+16)+8=0

We get rid of parentheses

3x-7x-16+8=0

We add all the numbers together, and all the variables

-4x-8=0

We move all terms containing x to the left, all other terms to the right

-4x=8

x=8/-4

x=-2

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