-(x-5)=3(x-3)+2

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Solution for -(x-5)=3(x-3)+2 equation: 



-(x-5)=3(x-3)+2

We move all terms to the left:

-(x-5)-(3(x-3)+2)=0

We get rid of parentheses

-x-(3(x-3)+2)+5=0



We calculate terms in parentheses: -(3(x-3)+2), so:

3(x-3)+2

We multiply parentheses

3x-9+2

We add all the numbers together, and all the variables

3x-7

Back to the equation:

-(3x-7)



We add all the numbers together, and all the variables

-1x-(3x-7)+5=0

We get rid of parentheses

-1x-3x+7+5=0

We add all the numbers together, and all the variables

-4x+12=0

We move all terms containing x to the left, all other terms to the right

-4x=-12

x=-12/-4

x=+3

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