-(x-3)-4(2x+1)=56

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Solution for -(x-3)-4(2x+1)=56 equation: 



-(x-3)-4(2x+1)=56

We move all terms to the left:

-(x-3)-4(2x+1)-(56)=0

We multiply parentheses

-(x-3)-8x-4-56=0

We get rid of parentheses

-x-8x+3-4-56=0

We add all the numbers together, and all the variables

-9x-57=0

We move all terms containing x to the left, all other terms to the right

-9x=57

x=57/-9

x=-6+1/3

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