-(x-2(3-x)-2)=2

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Solution for -(x-2(3-x)-2)=2 equation: 



-(x-2(3-x)-2)=2

We move all terms to the left:

-(x-2(3-x)-2)-(2)=0

We add all the numbers together, and all the variables

-(x-2(-1x+3)-2)-2=0



We calculate terms in parentheses: -(x-2(-1x+3)-2), so:

x-2(-1x+3)-2

We multiply parentheses

x+2x-6-2

We add all the numbers together, and all the variables

3x-8

Back to the equation:

-(3x-8)



We get rid of parentheses

-3x+8-2=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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