-(x-10)=2(3x-2)

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Solution for -(x-10)=2(3x-2) equation: 



-(x-10)=2(3x-2)

We move all terms to the left:

-(x-10)-(2(3x-2))=0

We get rid of parentheses

-x-(2(3x-2))+10=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We add all the numbers together, and all the variables

-1x-(6x-4)+10=0

We get rid of parentheses

-1x-6x+4+10=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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