-(x-1)+3(x-2)=4(x-1)+(x+2)

Solution for -(x-1)+3(x-2)=4(x-1)+(x+2) equation:

-(x-1)+3(x-2)=4(x-1)+(x+2)

We move all terms to the left:

-(x-1)+3(x-2)-(4(x-1)+(x+2))=0

We multiply parentheses

-(x-1)+3x-(4(x-1)+(x+2))-6=0

We get rid of parentheses

-x+3x-(4(x-1)+(x+2))+1-6=0


We calculate terms in parentheses: -(4(x-1)+(x+2)), so:

4(x-1)+(x+2)

We multiply parentheses

4x+(x+2)-4

We get rid of parentheses

4x+x+2-4

We add all the numbers together, and all the variables

5x-2

Back to the equation:

-(5x-2)


We add all the numbers together, and all the variables

2x-(5x-2)-5=0

We get rid of parentheses

2x-5x+2-5=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1