-(x+3)+4x=3(4x-5)-6

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Solution for -(x+3)+4x=3(4x-5)-6 equation: 



-(x+3)+4x=3(4x-5)-6

We move all terms to the left:

-(x+3)+4x-(3(4x-5)-6)=0

We add all the numbers together, and all the variables

4x-(x+3)-(3(4x-5)-6)=0

We get rid of parentheses

4x-x-(3(4x-5)-6)-3=0



We calculate terms in parentheses: -(3(4x-5)-6), so:

3(4x-5)-6

We multiply parentheses

12x-15-6

We add all the numbers together, and all the variables

12x-21

Back to the equation:

-(12x-21)



We add all the numbers together, and all the variables

3x-(12x-21)-3=0

We get rid of parentheses

3x-12x+21-3=0

We add all the numbers together, and all the variables

-9x+18=0

We move all terms containing x to the left, all other terms to the right

-9x=-18

x=-18/-9

x=+2

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