-(x+2)=1/2x+4

Solution for -(x+2)=1/2x+4 equation:

-(x+2)=1/2x+4

We move all terms to the left:

-(x+2)-(1/2x+4)=0


Domain of the equation: 2x+4)!=0

x∈R


We get rid of parentheses

-x-1/2x-2-4=0

We multiply all the terms by the denominator


-x*2x-2*2x-4*2x-1=0

Wy multiply elements

-2x^2-4x-8x-1=0

We add all the numbers together, and all the variables

-2x^2-12x-1=0

a = -2; b = -12; c = -1;
Δ = b2-4ac
Δ = -122-4·(-2)·(-1)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{34}}{2*-2}=\frac{12-2\sqrt{34}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{34}}{2*-2}=\frac{12+2\sqrt{34}}{-4}
$