-(x+1)(x+2)=0

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Solution for -(x+1)(x+2)=0 equation:


Simplifying
-1(x + 1)(x + 2) = 0

Reorder the terms:
-1(1 + x)(x + 2) = 0

Reorder the terms:
-1(1 + x)(2 + x) = 0

Multiply (1 + x) * (2 + x)
-1(1(2 + x) + x(2 + x)) = 0
-1((2 * 1 + x * 1) + x(2 + x)) = 0
-1((2 + 1x) + x(2 + x)) = 0
-1(2 + 1x + (2 * x + x * x)) = 0
-1(2 + 1x + (2x + x2)) = 0

Combine like terms: 1x + 2x = 3x
-1(2 + 3x + x2) = 0
(2 * -1 + 3x * -1 + x2 * -1) = 0
(-2 + -3x + -1x2) = 0

Solving
-2 + -3x + -1x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '-1'.
-1(2 + 3x + x2) = 0

Factor a trinomial.
-1((2 + x)(1 + x)) = 0

Ignore the factor -1.

Subproblem 1

Set the factor '(2 + x)' equal to zero and attempt to solve: Simplifying 2 + x = 0 Solving 2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Subproblem 2

Set the factor '(1 + x)' equal to zero and attempt to solve: Simplifying 1 + x = 0 Solving 1 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + x = 0 + -1 x = 0 + -1 Combine like terms: 0 + -1 = -1 x = -1 Simplifying x = -1

Solution

x = {-2, -1}

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