-(r-6)-8=(1+r)

Solution for -(r-6)-8=(1+r) equation:

-(r-6)-8=(1+r)

We move all terms to the left:

-(r-6)-8-((1+r))=0

We add all the numbers together, and all the variables

-(r-6)-((r+1))-8=0

We get rid of parentheses

-r-((r+1))+6-8=0


We calculate terms in parentheses: -((r+1)), so:

(r+1)

We get rid of parentheses

r+1

Back to the equation:

-(r+1)


We add all the numbers together, and all the variables

-1r-(r+1)-2=0

We get rid of parentheses

-1r-r-1-2=0

We add all the numbers together, and all the variables

-2r-3=0

We move all terms containing r to the left, all other terms to the right

-2r=3

r=3/-2

r=-1+1/2