-(n-5)=2(n+4)

Solution for -(n-5)=2(n+4) equation:

-(n-5)=2(n+4)

We move all terms to the left:

-(n-5)-(2(n+4))=0

We get rid of parentheses

-n-(2(n+4))+5=0


We calculate terms in parentheses: -(2(n+4)), so:

2(n+4)

We multiply parentheses

2n+8

Back to the equation:

-(2n+8)


We add all the numbers together, and all the variables

-1n-(2n+8)+5=0

We get rid of parentheses

-1n-2n-8+5=0

We add all the numbers together, and all the variables

-3n-3=0

We move all terms containing n to the left, all other terms to the right

-3n=3

n=3/-3

n=-1