-(n-5)+3(n+2)=2(n+3)+5

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Solution for -(n-5)+3(n+2)=2(n+3)+5 equation:


Simplifying
-1(n + -5) + 3(n + 2) = 2(n + 3) + 5

Reorder the terms:
-1(-5 + n) + 3(n + 2) = 2(n + 3) + 5
(-5 * -1 + n * -1) + 3(n + 2) = 2(n + 3) + 5
(5 + -1n) + 3(n + 2) = 2(n + 3) + 5

Reorder the terms:
5 + -1n + 3(2 + n) = 2(n + 3) + 5
5 + -1n + (2 * 3 + n * 3) = 2(n + 3) + 5
5 + -1n + (6 + 3n) = 2(n + 3) + 5

Reorder the terms:
5 + 6 + -1n + 3n = 2(n + 3) + 5

Combine like terms: 5 + 6 = 11
11 + -1n + 3n = 2(n + 3) + 5

Combine like terms: -1n + 3n = 2n
11 + 2n = 2(n + 3) + 5

Reorder the terms:
11 + 2n = 2(3 + n) + 5
11 + 2n = (3 * 2 + n * 2) + 5
11 + 2n = (6 + 2n) + 5

Reorder the terms:
11 + 2n = 6 + 5 + 2n

Combine like terms: 6 + 5 = 11
11 + 2n = 11 + 2n

Add '-11' to each side of the equation.
11 + -11 + 2n = 11 + -11 + 2n

Combine like terms: 11 + -11 = 0
0 + 2n = 11 + -11 + 2n
2n = 11 + -11 + 2n

Combine like terms: 11 + -11 = 0
2n = 0 + 2n
2n = 2n

Add '-2n' to each side of the equation.
2n + -2n = 2n + -2n

Combine like terms: 2n + -2n = 0
0 = 2n + -2n

Combine like terms: 2n + -2n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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