-(n-4)+6=3(n+2)

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Solution for -(n-4)+6=3(n+2) equation: 



-(n-4)+6=3(n+2)

We move all terms to the left:

-(n-4)+6-(3(n+2))=0

We get rid of parentheses

-n-(3(n+2))+4+6=0



We calculate terms in parentheses: -(3(n+2)), so:

3(n+2)

We multiply parentheses

3n+6

Back to the equation:

-(3n+6)



We add all the numbers together, and all the variables

-1n-(3n+6)+10=0

We get rid of parentheses

-1n-3n-6+10=0

We add all the numbers together, and all the variables

-4n+4=0

We move all terms containing n to the left, all other terms to the right

-4n=-4

n=-4/-4

n=1

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