-(n+4)+6=5(n-2)

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Solution for -(n+4)+6=5(n-2) equation:



-(n+4)+6=5(n-2)
We move all terms to the left:
-(n+4)+6-(5(n-2))=0
We get rid of parentheses
-n-(5(n-2))-4+6=0
We calculate terms in parentheses: -(5(n-2)), so:
5(n-2)
We multiply parentheses
5n-10
Back to the equation:
-(5n-10)
We add all the numbers together, and all the variables
-1n-(5n-10)+2=0
We get rid of parentheses
-1n-5n+10+2=0
We add all the numbers together, and all the variables
-6n+12=0
We move all terms containing n to the left, all other terms to the right
-6n=-12
n=-12/-6
n=+2

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