-(n+1)-2(-1-3n)=41

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Solution for -(n+1)-2(-1-3n)=41 equation: 



-(n+1)-2(-1-3n)=41

We move all terms to the left:

-(n+1)-2(-1-3n)-(41)=0

We add all the numbers together, and all the variables

-(n+1)-2(-3n-1)-41=0

We multiply parentheses

-(n+1)+6n+2-41=0

We get rid of parentheses

-n+6n-1+2-41=0

We add all the numbers together, and all the variables

5n-40=0

We move all terms containing n to the left, all other terms to the right

5n=40

n=40/5

n=8

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