-(m=3)+2(1+m)

Solution for -(m=3)+2(1+m) equation:

-(m=3)+2(1+m)

We move all terms to the left:

-(m-(3)+2(1+m))=0

We add all the numbers together, and all the variables

-(m-3+2(m+1))=0


We calculate terms in parentheses: -(m-3+2(m+1)), so:

m-3+2(m+1)

determiningTheFunctionDomain
m+2(m+1)-3

We multiply parentheses

m+2m+2-3

We add all the numbers together, and all the variables

3m-1

Back to the equation:

-(3m-1)


We get rid of parentheses

-3m+1=0

We move all terms containing m to the left, all other terms to the right

-3m=-1

m=-1/-3

m=1/3