-(c+20)=6(5+4c)

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Solution for -(c+20)=6(5+4c) equation:



-(c+20)=6(5+4c)
We move all terms to the left:
-(c+20)-(6(5+4c))=0
We add all the numbers together, and all the variables
-(c+20)-(6(4c+5))=0
We get rid of parentheses
-c-(6(4c+5))-20=0
We calculate terms in parentheses: -(6(4c+5)), so:
6(4c+5)
We multiply parentheses
24c+30
Back to the equation:
-(24c+30)
We add all the numbers together, and all the variables
-1c-(24c+30)-20=0
We get rid of parentheses
-1c-24c-30-20=0
We add all the numbers together, and all the variables
-25c-50=0
We move all terms containing c to the left, all other terms to the right
-25c=50
c=50/-25
c=-2

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