-(c+2)=4(c+1)

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Solution for -(c+2)=4(c+1) equation: 



-(c+2)=4(c+1)

We move all terms to the left:

-(c+2)-(4(c+1))=0

We get rid of parentheses

-c-(4(c+1))-2=0



We calculate terms in parentheses: -(4(c+1)), so:

4(c+1)

We multiply parentheses

4c+4

Back to the equation:

-(4c+4)



We add all the numbers together, and all the variables

-1c-(4c+4)-2=0

We get rid of parentheses

-1c-4c-4-2=0

We add all the numbers together, and all the variables

-5c-6=0

We move all terms containing c to the left, all other terms to the right

-5c=6

c=6/-5

c=-1+1/5

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