-(9x-4)-(4x-5)+8=-12(x-1)-(6x+13)+3

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Solution for -(9x-4)-(4x-5)+8=-12(x-1)-(6x+13)+3 equation: 



-(9x-4)-(4x-5)+8=-12(x-1)-(6x+13)+3

We move all terms to the left:

-(9x-4)-(4x-5)+8-(-12(x-1)-(6x+13)+3)=0

We get rid of parentheses

-9x-4x-(-12(x-1)-(6x+13)+3)+4+5+8=0



We calculate terms in parentheses: -(-12(x-1)-(6x+13)+3), so:

-12(x-1)-(6x+13)+3

We multiply parentheses

-12x-(6x+13)+12+3

We get rid of parentheses

-12x-6x-13+12+3

We add all the numbers together, and all the variables

-18x+2

Back to the equation:

-(-18x+2)



We add all the numbers together, and all the variables

-13x-(-18x+2)+17=0

We get rid of parentheses

-13x+18x-2+17=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3

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