-(8x+2)+4x=-3(x-1)+6

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Solution for -(8x+2)+4x=-3(x-1)+6 equation: 



-(8x+2)+4x=-3(x-1)+6

We move all terms to the left:

-(8x+2)+4x-(-3(x-1)+6)=0

We add all the numbers together, and all the variables

4x-(8x+2)-(-3(x-1)+6)=0

We get rid of parentheses

4x-8x-(-3(x-1)+6)-2=0



We calculate terms in parentheses: -(-3(x-1)+6), so:

-3(x-1)+6

We multiply parentheses

-3x+3+6

We add all the numbers together, and all the variables

-3x+9

Back to the equation:

-(-3x+9)



We add all the numbers together, and all the variables

-4x-(-3x+9)-2=0

We get rid of parentheses

-4x+3x-9-2=0

We add all the numbers together, and all the variables

-1x-11=0

We move all terms containing x to the left, all other terms to the right

-x=11

x=11/-1

x=-11

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