-(8-3x)=-2(1-x)+6x

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Solution for -(8-3x)=-2(1-x)+6x equation: 



-(8-3x)=-2(1-x)+6x

We move all terms to the left:

-(8-3x)-(-2(1-x)+6x)=0

We add all the numbers together, and all the variables

-(-3x+8)-(-2(-1x+1)+6x)=0

We get rid of parentheses

3x-(-2(-1x+1)+6x)-8=0



We calculate terms in parentheses: -(-2(-1x+1)+6x), so:

-2(-1x+1)+6x

We add all the numbers together, and all the variables

6x-2(-1x+1)

We multiply parentheses

6x+2x-2

We add all the numbers together, and all the variables

8x-2

Back to the equation:

-(8x-2)



We get rid of parentheses

3x-8x+2-8=0

We add all the numbers together, and all the variables

-5x-6=0

We move all terms containing x to the left, all other terms to the right

-5x=6

x=6/-5

x=-1+1/5

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