-(7z-(13z+2))=2+(5z+0)

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Solution for -(7z-(13z+2))=2+(5z+0) equation:


Simplifying
-1(7z + -1(13z + 2)) = 2 + (5z + 0)

Reorder the terms:
-1(7z + -1(2 + 13z)) = 2 + (5z + 0)
-1(7z + (2 * -1 + 13z * -1)) = 2 + (5z + 0)
-1(7z + (-2 + -13z)) = 2 + (5z + 0)

Reorder the terms:
-1(-2 + 7z + -13z) = 2 + (5z + 0)

Combine like terms: 7z + -13z = -6z
-1(-2 + -6z) = 2 + (5z + 0)
(-2 * -1 + -6z * -1) = 2 + (5z + 0)
(2 + 6z) = 2 + (5z + 0)

Reorder the terms:
2 + 6z = 2 + (0 + 5z)
Remove the zero:
2 + 6z = 2 + (5z)
2 + 6z = 2 + (5z)

Add '-2' to each side of the equation.
2 + -2 + 6z = 2 + -2 + (5z)

Combine like terms: 2 + -2 = 0
0 + 6z = 2 + -2 + (5z)
6z = 2 + -2 + (5z)

Combine like terms: 2 + -2 = 0
6z = 0 + (5z)
6z = (5z)

Solving
6z = (5z)

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '(-5z)' to each side of the equation.
6z + (-5z) = (5z) + (-5z)

Combine like terms: 6z + (-5z) = 1z
1z = (5z) + (-5z)

Combine like terms: (5z) + (-5z) = 0
1z = 0

Divide each side by '1'.
z = 0

Simplifying
z = 0

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