-(7b-6)+6(3b+8)=7+3b+5b-1

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Solution for -(7b-6)+6(3b+8)=7+3b+5b-1 equation:



-(7b-6)+6(3b+8)=7+3b+5b-1
We move all terms to the left:
-(7b-6)+6(3b+8)-(7+3b+5b-1)=0
We add all the numbers together, and all the variables
-(7b-6)+6(3b+8)-(8b+6)=0
We multiply parentheses
-(7b-6)+18b-(8b+6)+48=0
We get rid of parentheses
-7b+18b-8b+6-6+48=0
We add all the numbers together, and all the variables
3b+48=0
We move all terms containing b to the left, all other terms to the right
3b=-48
b=-48/3
b=-16

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