-(6x-4)=2(-8x-4)+22

Solution for -(6x-4)=2(-8x-4)+22 equation:

-(6x-4)=2(-8x-4)+22

We move all terms to the left:

-(6x-4)-(2(-8x-4)+22)=0

We get rid of parentheses

-6x-(2(-8x-4)+22)+4=0


We calculate terms in parentheses: -(2(-8x-4)+22), so:

2(-8x-4)+22

We multiply parentheses

-16x-8+22

We add all the numbers together, and all the variables

-16x+14

Back to the equation:

-(-16x+14)


We get rid of parentheses

-6x+16x-14+4=0

We add all the numbers together, and all the variables

10x-10=0

We move all terms containing x to the left, all other terms to the right

10x=10

x=10/10

x=1