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-(6n-5)=2-3(n-1)
We move all terms to the left:
-(6n-5)-(2-3(n-1))=0
We get rid of parentheses
-6n-(2-3(n-1))+5=0
We calculate terms in parentheses: -(2-3(n-1)), so:We get rid of parentheses
2-3(n-1)
determiningTheFunctionDomain -3(n-1)+2
We multiply parentheses
-3n+3+2
We add all the numbers together, and all the variables
-3n+5
Back to the equation:
-(-3n+5)
-6n+3n-5+5=0
We add all the numbers together, and all the variables
-3n=0
n=0/-3
n=0
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