-(5y-2)+4=-2(3y-6)-10

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Solution for -(5y-2)+4=-2(3y-6)-10 equation: 



-(5y-2)+4=-2(3y-6)-10

We move all terms to the left:

-(5y-2)+4-(-2(3y-6)-10)=0

We get rid of parentheses

-5y-(-2(3y-6)-10)+2+4=0



We calculate terms in parentheses: -(-2(3y-6)-10), so:

-2(3y-6)-10

We multiply parentheses

-6y+12-10

We add all the numbers together, and all the variables

-6y+2

Back to the equation:

-(-6y+2)



We add all the numbers together, and all the variables

-5y-(-6y+2)+6=0

We get rid of parentheses

-5y+6y-2+6=0

We add all the numbers together, and all the variables

y+4=0

We move all terms containing y to the left, all other terms to the right

y=-4

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