-(5x-5)+10x=2(-5x-40)

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Solution for -(5x-5)+10x=2(-5x-40) equation: 



-(5x-5)+10x=2(-5x-40)

We move all terms to the left:

-(5x-5)+10x-(2(-5x-40))=0

We add all the numbers together, and all the variables

10x-(5x-5)-(2(-5x-40))=0

We get rid of parentheses

10x-5x-(2(-5x-40))+5=0



We calculate terms in parentheses: -(2(-5x-40)), so:

2(-5x-40)

We multiply parentheses

-10x-80

Back to the equation:

-(-10x-80)



We add all the numbers together, and all the variables

5x-(-10x-80)+5=0

We get rid of parentheses

5x+10x+80+5=0

We add all the numbers together, and all the variables

15x+85=0

We move all terms containing x to the left, all other terms to the right

15x=-85

x=-85/15

x=-5+2/3

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