-(5x-3)-(9x-2)+6=-7(x-4)-(9x+3)+2

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Solution for -(5x-3)-(9x-2)+6=-7(x-4)-(9x+3)+2 equation: 



-(5x-3)-(9x-2)+6=-7(x-4)-(9x+3)+2

We move all terms to the left:

-(5x-3)-(9x-2)+6-(-7(x-4)-(9x+3)+2)=0

We get rid of parentheses

-5x-9x-(-7(x-4)-(9x+3)+2)+3+2+6=0



We calculate terms in parentheses: -(-7(x-4)-(9x+3)+2), so:

-7(x-4)-(9x+3)+2

We multiply parentheses

-7x-(9x+3)+28+2

We get rid of parentheses

-7x-9x-3+28+2

We add all the numbers together, and all the variables

-16x+27

Back to the equation:

-(-16x+27)



We add all the numbers together, and all the variables

-14x-(-16x+27)+11=0

We get rid of parentheses

-14x+16x-27+11=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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