-(5/4)(x-5)+(1/4)x=3

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Solution for -(5/4)(x-5)+(1/4)x=3 equation: 



-(5/4)(x-5)+(1/4)x=3

We move all terms to the left:

-(5/4)(x-5)+(1/4)x-(3)=0



Domain of the equation: 4)(x-5)!=0

x∈R





Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(+5/4)(x-5)+(+1/4)x-3=0

We multiply parentheses

x^2-(+5/4)(x-5)-3=0

We multiply parentheses ..

x^2-(+5x^2+5/4*-5)-3=0

We multiply all the terms by the denominator


5x^2+x^2*4*+5-5)-(-3*4*-5)=0

We add all the numbers together, and all the variables

5x^2+x^2*4*+5-5)-60=0

We add all the numbers together, and all the variables

5x^2+x^2*4*=0

Wy multiply elements

5x^2+4x^3=0

We do not support expression: x^3

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