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-(5/2)x=5
We move all terms to the left:
-(5/2)x-(5)=0
Domain of the equation: 2)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+5/2)x-5=0
We multiply parentheses
-5x^2-5=0
a = -5; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-5)·(-5)
Δ = -100
Delta is less than zero, so there is no solution for the equation
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