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-(5-3k)=-8+2(k-2)
We move all terms to the left:
-(5-3k)-(-8+2(k-2))=0
We add all the numbers together, and all the variables
-(-3k+5)-(-8+2(k-2))=0
We get rid of parentheses
3k-(-8+2(k-2))-5=0
We calculate terms in parentheses: -(-8+2(k-2)), so:We get rid of parentheses
-8+2(k-2)
determiningTheFunctionDomain 2(k-2)-8
We multiply parentheses
2k-4-8
We add all the numbers together, and all the variables
2k-12
Back to the equation:
-(2k-12)
3k-2k+12-5=0
We add all the numbers together, and all the variables
k+7=0
We move all terms containing k to the left, all other terms to the right
k=-7
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