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-(5+2a=-65
We move all terms to the left:
-(5+2a-(-65)=0
We calculate terms in parentheses: -(5+2a-(-65), so:a=0/-2
5+2a-(-65
determiningTheFunctionDomain 2a+5-(-65
We add all the numbers together, and all the variables
2a
Back to the equation:
-(2a)
a=0
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