-(4y+6)=2(4-y)

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Solution for -(4y+6)=2(4-y) equation: 



-(4y+6)=2(4-y)

We move all terms to the left:

-(4y+6)-(2(4-y))=0

We add all the numbers together, and all the variables

-(4y+6)-(2(-1y+4))=0

We get rid of parentheses

-4y-(2(-1y+4))-6=0



We calculate terms in parentheses: -(2(-1y+4)), so:

2(-1y+4)

We multiply parentheses

-2y+8

Back to the equation:

-(-2y+8)



We get rid of parentheses

-4y+2y-8-6=0

We add all the numbers together, and all the variables

-2y-14=0

We move all terms containing y to the left, all other terms to the right

-2y=14

y=14/-2

y=-7

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