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-(4x-5)-(9x-5)+7=-11(x-1)-(5x+12)+3
We move all terms to the left:
-(4x-5)-(9x-5)+7-(-11(x-1)-(5x+12)+3)=0
We get rid of parentheses
-4x-9x-(-11(x-1)-(5x+12)+3)+5+5+7=0
We calculate terms in parentheses: -(-11(x-1)-(5x+12)+3), so:We add all the numbers together, and all the variables
-11(x-1)-(5x+12)+3
We multiply parentheses
-11x-(5x+12)+11+3
We get rid of parentheses
-11x-5x-12+11+3
We add all the numbers together, and all the variables
-16x+2
Back to the equation:
-(-16x+2)
-13x-(-16x+2)+17=0
We get rid of parentheses
-13x+16x-2+17=0
We add all the numbers together, and all the variables
3x+15=0
We move all terms containing x to the left, all other terms to the right
3x=-15
x=-15/3
x=-5
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