-(4x-4)-(4x-5)+10=-8(x-1)-(4x+8)+3

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Solution for -(4x-4)-(4x-5)+10=-8(x-1)-(4x+8)+3 equation: 



-(4x-4)-(4x-5)+10=-8(x-1)-(4x+8)+3

We move all terms to the left:

-(4x-4)-(4x-5)+10-(-8(x-1)-(4x+8)+3)=0

We get rid of parentheses

-4x-4x-(-8(x-1)-(4x+8)+3)+4+5+10=0



We calculate terms in parentheses: -(-8(x-1)-(4x+8)+3), so:

-8(x-1)-(4x+8)+3

We multiply parentheses

-8x-(4x+8)+8+3

We get rid of parentheses

-8x-4x-8+8+3

We add all the numbers together, and all the variables

-12x+3

Back to the equation:

-(-12x+3)



We add all the numbers together, and all the variables

-8x-(-12x+3)+19=0

We get rid of parentheses

-8x+12x-3+19=0

We add all the numbers together, and all the variables

4x+16=0

We move all terms containing x to the left, all other terms to the right

4x=-16

x=-16/4

x=-4

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