-(4b-3)=3(1-3b)+5b

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Solution for -(4b-3)=3(1-3b)+5b equation:


Simplifying
-1(4b + -3) = 3(1 + -3b) + 5b

Reorder the terms:
-1(-3 + 4b) = 3(1 + -3b) + 5b
(-3 * -1 + 4b * -1) = 3(1 + -3b) + 5b
(3 + -4b) = 3(1 + -3b) + 5b
3 + -4b = (1 * 3 + -3b * 3) + 5b
3 + -4b = (3 + -9b) + 5b

Combine like terms: -9b + 5b = -4b
3 + -4b = 3 + -4b

Add '-3' to each side of the equation.
3 + -3 + -4b = 3 + -3 + -4b

Combine like terms: 3 + -3 = 0
0 + -4b = 3 + -3 + -4b
-4b = 3 + -3 + -4b

Combine like terms: 3 + -3 = 0
-4b = 0 + -4b
-4b = -4b

Add '4b' to each side of the equation.
-4b + 4b = -4b + 4b

Combine like terms: -4b + 4b = 0
0 = -4b + 4b

Combine like terms: -4b + 4b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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