-(3y-8)=-4(y-2)+y

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Solution for -(3y-8)=-4(y-2)+y equation:


Simplifying
-1(3y + -8) = -4(y + -2) + y

Reorder the terms:
-1(-8 + 3y) = -4(y + -2) + y
(-8 * -1 + 3y * -1) = -4(y + -2) + y
(8 + -3y) = -4(y + -2) + y

Reorder the terms:
8 + -3y = -4(-2 + y) + y
8 + -3y = (-2 * -4 + y * -4) + y
8 + -3y = (8 + -4y) + y

Combine like terms: -4y + y = -3y
8 + -3y = 8 + -3y

Add '-8' to each side of the equation.
8 + -8 + -3y = 8 + -8 + -3y

Combine like terms: 8 + -8 = 0
0 + -3y = 8 + -8 + -3y
-3y = 8 + -8 + -3y

Combine like terms: 8 + -8 = 0
-3y = 0 + -3y
-3y = -3y

Add '3y' to each side of the equation.
-3y + 3y = -3y + 3y

Combine like terms: -3y + 3y = 0
0 = -3y + 3y

Combine like terms: -3y + 3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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