-(3y-5)=-4(3y+1)+9y

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Solution for -(3y-5)=-4(3y+1)+9y equation: 



-(3y-5)=-4(3y+1)+9y

We move all terms to the left:

-(3y-5)-(-4(3y+1)+9y)=0

We get rid of parentheses

-3y-(-4(3y+1)+9y)+5=0



We calculate terms in parentheses: -(-4(3y+1)+9y), so:

-4(3y+1)+9y

We add all the numbers together, and all the variables

9y-4(3y+1)

We multiply parentheses

9y-12y-4

We add all the numbers together, and all the variables

-3y-4

Back to the equation:

-(-3y-4)



We get rid of parentheses

-3y+3y+4+5=0

We add all the numbers together, and all the variables

9!=0

There is no solution for this equation

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