-(3y-4)-(-2y+2)=3

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Solution for -(3y-4)-(-2y+2)=3 equation:


Simplifying
-1(3y + -4) + -1(-2y + 2) = 3

Reorder the terms:
-1(-4 + 3y) + -1(-2y + 2) = 3
(-4 * -1 + 3y * -1) + -1(-2y + 2) = 3
(4 + -3y) + -1(-2y + 2) = 3

Reorder the terms:
4 + -3y + -1(2 + -2y) = 3
4 + -3y + (2 * -1 + -2y * -1) = 3
4 + -3y + (-2 + 2y) = 3

Reorder the terms:
4 + -2 + -3y + 2y = 3

Combine like terms: 4 + -2 = 2
2 + -3y + 2y = 3

Combine like terms: -3y + 2y = -1y
2 + -1y = 3

Solving
2 + -1y = 3

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1y = 3 + -2

Combine like terms: 2 + -2 = 0
0 + -1y = 3 + -2
-1y = 3 + -2

Combine like terms: 3 + -2 = 1
-1y = 1

Divide each side by '-1'.
y = -1

Simplifying
y = -1

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