-(3y+4)-(2y-5)=1

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Solution for -(3y+4)-(2y-5)=1 equation: 


Simplifying
-1(3y + 4) + -1(2y + -5) = 1

Reorder the terms:
-1(4 + 3y) + -1(2y + -5) = 1
(4 * -1 + 3y * -1) + -1(2y + -5) = 1
(-4 + -3y) + -1(2y + -5) = 1

Reorder the terms:
-4 + -3y + -1(-5 + 2y) = 1
-4 + -3y + (-5 * -1 + 2y * -1) = 1
-4 + -3y + (5 + -2y) = 1

Reorder the terms:
-4 + 5 + -3y + -2y = 1

Combine like terms: -4 + 5 = 1
1 + -3y + -2y = 1

Combine like terms: -3y + -2y = -5y
1 + -5y = 1

Add '-1' to each side of the equation.
1 + -1 + -5y = 1 + -1

Combine like terms: 1 + -1 = 0
0 + -5y = 1 + -1
-5y = 1 + -1

Combine like terms: 1 + -1 = 0
-5y = 0

Solving
-5y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '-5'.
y = 0

Simplifying
y = 0

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