-(3y+2)-(-2y-4)=1

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Solution for -(3y+2)-(-2y-4)=1 equation: 


Simplifying
-1(3y + 2) + -1(-2y + -4) = 1

Reorder the terms:
-1(2 + 3y) + -1(-2y + -4) = 1
(2 * -1 + 3y * -1) + -1(-2y + -4) = 1
(-2 + -3y) + -1(-2y + -4) = 1

Reorder the terms:
-2 + -3y + -1(-4 + -2y) = 1
-2 + -3y + (-4 * -1 + -2y * -1) = 1
-2 + -3y + (4 + 2y) = 1

Reorder the terms:
-2 + 4 + -3y + 2y = 1

Combine like terms: -2 + 4 = 2
2 + -3y + 2y = 1

Combine like terms: -3y + 2y = -1y
2 + -1y = 1

Solving
2 + -1y = 1

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1y = 1 + -2

Combine like terms: 2 + -2 = 0
0 + -1y = 1 + -2
-1y = 1 + -2

Combine like terms: 1 + -2 = -1
-1y = -1

Divide each side by '-1'.
y = 1

Simplifying
y = 1

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