-(3y+-2)-3y=2y-4y+7

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Solution for -(3y+-2)-3y=2y-4y+7 equation:



-(3y+-2)-3y=2y-4y+7
We move all terms to the left:
-(3y+-2)-3y-(2y-4y+7)=0
We add all the numbers together, and all the variables
-(3y-2)-3y-(-2y+7)=0
We add all the numbers together, and all the variables
-3y-(3y-2)-(-2y+7)=0
We get rid of parentheses
-3y-3y+2y+2-7=0
We add all the numbers together, and all the variables
-4y-5=0
We move all terms containing y to the left, all other terms to the right
-4y=5
y=5/-4
y=-1+1/4

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