-(3x2)-(x-1)=-(2x-2)-(2x+4)

Solution for -(3x2)-(x-1)=-(2x-2)-(2x+4) equation:

-(3x^2)-(x-1)=-(2x-2)-(2x+4)

We move all terms to the left:

-(3x^2)-(x-1)-(-(2x-2)-(2x+4))=0

We get rid of parentheses

-3x^2-x-(-(2x-2)-(2x+4))+1=0


We calculate terms in parentheses: -(-(2x-2)-(2x+4)), so:

-(2x-2)-(2x+4)

We get rid of parentheses

-2x-2x+2-4

We add all the numbers together, and all the variables

-4x-2

Back to the equation:

-(-4x-2)


We add all the numbers together, and all the variables

-3x^2-1x-(-4x-2)+1=0

We get rid of parentheses

-3x^2-1x+4x+2+1=0

We add all the numbers together, and all the variables

-3x^2+3x+3=0

a = -3; b = 3; c = +3;
Δ = b2-4ac
Δ = 32-4·(-3)·3
Δ = 45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{45}=\sqrt{9*5}=\sqrt{9}*\sqrt{5}=3\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{5}}{2*-3}=\frac{-3-3\sqrt{5}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{5}}{2*-3}=\frac{-3+3\sqrt{5}}{-6}
$