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-(3x-2)=5+3(2x+5)
We move all terms to the left:
-(3x-2)-(5+3(2x+5))=0
We get rid of parentheses
-3x-(5+3(2x+5))+2=0
We calculate terms in parentheses: -(5+3(2x+5)), so:We get rid of parentheses
5+3(2x+5)
determiningTheFunctionDomain 3(2x+5)+5
We multiply parentheses
6x+15+5
We add all the numbers together, and all the variables
6x+20
Back to the equation:
-(6x+20)
-3x-6x-20+2=0
We add all the numbers together, and all the variables
-9x-18=0
We move all terms containing x to the left, all other terms to the right
-9x=18
x=18/-9
x=-2
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