-(3x-2)-(2x-2)+4=-7(x-5)-(2x+8)+8

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Solution for -(3x-2)-(2x-2)+4=-7(x-5)-(2x+8)+8 equation: 



-(3x-2)-(2x-2)+4=-7(x-5)-(2x+8)+8

We move all terms to the left:

-(3x-2)-(2x-2)+4-(-7(x-5)-(2x+8)+8)=0

We get rid of parentheses

-3x-2x-(-7(x-5)-(2x+8)+8)+2+2+4=0



We calculate terms in parentheses: -(-7(x-5)-(2x+8)+8), so:

-7(x-5)-(2x+8)+8

We multiply parentheses

-7x-(2x+8)+35+8

We get rid of parentheses

-7x-2x-8+35+8

We add all the numbers together, and all the variables

-9x+35

Back to the equation:

-(-9x+35)



We add all the numbers together, and all the variables

-5x-(-9x+35)+8=0

We get rid of parentheses

-5x+9x-35+8=0

We add all the numbers together, and all the variables

4x-27=0

We move all terms containing x to the left, all other terms to the right

4x=27

x=27/4

x=6+3/4

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