-(3b-20)=6(2b+5)

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Solution for -(3b-20)=6(2b+5) equation: 



-(3b-20)=6(2b+5)

We move all terms to the left:

-(3b-20)-(6(2b+5))=0

We get rid of parentheses

-3b-(6(2b+5))+20=0



We calculate terms in parentheses: -(6(2b+5)), so:

6(2b+5)

We multiply parentheses

12b+30

Back to the equation:

-(12b+30)



We get rid of parentheses

-3b-12b-30+20=0

We add all the numbers together, and all the variables

-15b-10=0

We move all terms containing b to the left, all other terms to the right

-15b=10

b=10/-15

b=-2/3

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